kernel space getcwd()? (using current() to find out cwd)
This is probably a stupid question, and probably directed to the wrong list. Apologies in advance, but I'm stumped
I've been working on a kernel module to report on "changed files". It works just fine -- I wrap the orignal system calls with my replacements which queue the filenames being modified, and when another proccess reads from the device or proc entry, they get a nice snapshot of what's going on in the system -- except that all the paths are relative to the calling process.
So, a little ignorance being a dangerous thing, I thought I'd be clever and manually reconstruct the full path by walking up current->fs->pwd->d_parent and padding d_name to the filename until it hits root.
Unfortunatly, this approach causes kernel panics. e.g., the attached code snippet will inevitably bring down the machine if I call it during in my replacement open, mkdir, rmdir, unlink routines -- and tehy all work fine without itq.
What am I not getting? I do see, before I go down, that there's a few occasions where current() is NULL...
Apologies in advance for a wordy, probably stupid question, but I'm stumped.
If this is not the right approach for what I'm trying to do (e.g. a kernel space getcwd()), can someone point me to something else I can try?
Thanks in advance,
Mike Welles
----------------------------------------
(this is the greatly reduced version which does nothing but try and reference current->fs->pwd)
void fill_full_path(char *name)
{
if (current==NULL)
{
#ifdef DEBUG
printk("ERROR! current == NULL\n");
#endif
return;
}if (current->fs==NULL)
{
#ifdef DEBUG
printk("ERROR! current-> == NULL\n");
#endif
return;
}if (current->fs->pwd==NULL)
{
#ifdef DEBUG
printk("ERROR! current->fs->pwd == NULL\n");
#endif
return;
}
return;
}This is probably a stupid question: I've been working on a kernel module to report on "changed files".
It works just fine -- I wrap the orignal system calls with my replacements which queue the filenames being modified, and when another proccess reads from the device or proc entry, they get a nice snapshot of what's going on in the system -- except that all the paths are relative to the calling process.
So, a little ignorance being a dangerous thing, I thought I'd be clever and manually reconstruct the full path by walking up current->fs->pwd->d_parent and padding d_name to the filename until it hits root.
Unfortunatly, this approach causes kernel panics. e.g., the attached code snippet will inevitably bring down the machine if I call it during in my replacement open, mkdir, rmdir, unlink routines -- and tehy all work fine without itq.
What am I not getting? I do see, before I go down, that there's a few occasions where current() is NULL...
Apologies in advance for a wordy, probably stupid question, but I'm stumped.
If this is not the right approach for what I'm trying to do (e.g. a kernel space getcwd()), can someone point me to where I should look?
Thanks in advance,
Mike Welles
----------------------------------------
(this is the greatly reduced version which does nothing but try and reference current->fs->pwd)
void fill_full_path(char *name)
{
if (current==NULL)
{
#ifdef DEBUG
printk("ERROR! current == NULL\n");
#endif
return;
}if (current->fs==NULL)
{
#ifdef DEBUG
printk("ERROR! current-> == NULL\n");
#endif
return;
}if (current->fs->pwd==NULL)
{
#ifdef DEBUG
printk("ERROR! current->fs->pwd == NULL\n");
#endif
return;
}
return;
}Quoted 9 lines · In article <[email protected]> you wrote:
So, a little ignorance being a dangerous thing, I thought I'd be clever and manually reconstruct the full path by walking up
current->fs->pwd->d_parentand paddingd_nameto the filename until it hits root.Unfortunatly, this approach causes kernel panics. e.g., the attached code snippet will inevitably bring down the machine if I call it during in my replacement open, mkdir, rmdir, unlink routines -- and tehy all work fine without itq.
Use d_path. NOTE: the buffer in which the pathname is returned is the return value of the function and _not_ the buffer you gave to it.
Christoph
Signature · 1 line
Of course it doesn't work. We've performed a software upgrade.