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UML - memcpy export needs to follow host declaration

PATCH In review Jeff Dike 1 participant 1 message Jun 3, 2008 User-mode Linux (UML)

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Jeff Dike

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PATCH 4/6 UML - memcpy export needs to follow host declaration

x86_64 defines either memcpy or __memcpy depending on the gcc version, and it looks like UML needs to follow that in its exporting.

Cc Gabriel C <[email protected]>
Signed-off-by Jeff Dike <[email protected]>
---
 arch/um/sys-x86_64/ksyms.c |    4 ++++
 1 file changed, 4 insertions(+)
arch/um/sys-x86_64/ksyms.c +4 -0
Index: linux-2.6-git/arch/um/sys-x86_64/ksyms.c
===================================================================
@@ -3,5 +3,9 @@
 #include <asm/checksum.h>
 
 /*XXX: we need them because they would be exported by x86_64 */
+#if (__GNUC__ == 4 && __GNUC_MINOR__ >= 3) || __GNUC__ > 4
+EXPORT_SYMBOL(memcpy);
+#else
 EXPORT_SYMBOL(__memcpy);
+#endif
 EXPORT_SYMBOL(csum_partial);

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