libceph: fix error handling in handle_reply()

We've tried to fix the error paths in this function before, but there is still a hidden goto in the ceph_decode_need() macro which goes to the wrong place. We need to release the "req" and unlock a mutex before returning.

Signed-off-by Dan Carpenter <[email protected]>

net/ceph/osd_client.c +3 -4

index dbc0a73..559a832 100644
@@ -1488,14 +1488,14 @@ static void handle_reply(struct ceph_osd_client *osdc, struct ceph_msg *msg,
 	dout("handle_reply %p tid %llu req %p result %d\n", msg, tid,
 	     req, result);
 
-	ceph_decode_need(&p, end, 4, bad);
+	ceph_decode_need(&p, end, 4, bad_put);
 	numops = ceph_decode_32(&p);
 	if (numops > CEPH_OSD_MAX_OP)
 		goto bad_put;
 	if (numops != req->r_num_ops)
 		goto bad_put;
 	payload_len = 0;
-	ceph_decode_need(&p, end, numops * sizeof(struct ceph_osd_op), bad);
+	ceph_decode_need(&p, end, numops * sizeof(struct ceph_osd_op), bad_put);
 	for (i = 0; i < numops; i++) {
 		struct ceph_osd_op *op = p;
 		int len;

@@ -1513,7 +1513,7 @@ static void handle_reply(struct ceph_osd_client *osdc, struct ceph_msg *msg,
 		goto bad_put;
 	}
 
-	ceph_decode_need(&p, end, 4 + numops * 4, bad);
+	ceph_decode_need(&p, end, 4 + numops * 4, bad_put);
 	retry_attempt = ceph_decode_32(&p);
 	for (i = 0; i < numops; i++)
 		req->r_reply_op_result[i] = ceph_decode_32(&p);
--

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