TCP fast open question
Subsystems (2)
Hi all,
Now we are trying to use TCP fast open in our nginx server, and we encounter a problem under non-blocking socket. I appreciate if some one can reply this question. Thanks in advance.
I describe our question here. we have two machines, one is as server and another is as client. 'net.ipv4.tcp_fastopen' on both of them are set to
3. The server program looks like below:
... listenfd = socket(AF_INET, SOCK_STREAM, 0); bind(listenfd, (struct sockaddr *)&servaddr, sizeof(servaddr)); int tfo_opt = 1; setsockopt(listenfd, SOL_TCP, TCP_LISTEN_INFO, &tfo_opt, sizeof(tfo_opt)); listen(listenfd, 5); connfd = accept(listenfd, (struct sockaddr *)NULL, NULL); recv(connfd, &buf, 4096) ...
The client program:
... sockfd = socket(AF_INET, SOCK_STREAM, 0); fcntl(sockfd, F_SETFL, fcntl(sockfd, F_GETFL, 0)|O_NONBLOCK); sendto(sockfd, msg, strlen(msg), MSG_FASTOPEN, (struct sockaddr *)&servaddr, sizeof(servaddr); recv(sockfd, buf, 4096, 0); ...
We use a non-blocking socket to connect the server and send some messages. After calling sendto(2) we always get an EINPROGRESS error. We think it is reasonable because connect(2) could also return this error with a non-blocking socket and the connection will be established later. The question is *whether or not the data will be sent* after the connection is established. If I understand correctly, sendto(2) will return the number of bytes of data queued up in the kernel or sent in the SYN packet. Even though the EINPROGRESS is returned. If sendto(2) returns -1, that means that no data is queued up in kernel or sent in the packet. Please correct me if I miss-understand something.
We run the program in our testing environment, and we use tcpdump(1) to capture the packets. From the result we can see there is no any data that is sent. Then we do another testing that after calling sendto(2) the client program will sleep for 5 seconds and then call send(2) to transfer some data.
$ ./client xx.xx.xx.xx ret -1 errno 115
The program works well. So that means that after getting a EINPROGRESS error, the program must call send(2) manually. Is it correct? If we want to avoid this problem, we need to set 'net.ipv4.tcp_fastopen' to 0x707 ?
Regards,
- Zheng
Quoted 10 lines · Zheng Liu
Hi all,
Now we are trying to use TCP fast open in our nginx server, and we encounter a problem under non-blocking socket. I appreciate if some one can reply this question. Thanks in advance.
I describe our question here. we have two machines, one is as server and another is as client. 'net.ipv4.tcp_fastopen' on both of them are set to
3. The server program looks like below:
Quoted 5 lines
... listenfd = socket(AF_INET, SOCK_STREAM, 0); bind(listenfd, (struct sockaddr *)&servaddr, sizeof(servaddr)); int tfo_opt = 1; setsockopt(listenfd, SOL_TCP, TCP_LISTEN_INFO, &tfo_opt, sizeof(tfo_opt));
s/TCP_LISTEN_INFO/TCP_FASTOPEN/??
Quoted 46 lines
listen(listenfd, 5); connfd = accept(listenfd, (struct sockaddr *)NULL, NULL); recv(connfd, &buf, 4096) ...The client program:
... sockfd = socket(AF_INET, SOCK_STREAM, 0); fcntl(sockfd, F_SETFL, fcntl(sockfd, F_GETFL, 0)|O_NONBLOCK); sendto(sockfd, msg, strlen(msg), MSG_FASTOPEN, (struct sockaddr *)&servaddr, sizeof(servaddr); recv(sockfd, buf, 4096, 0); ...We use a non-blocking socket to connect the server and send some messages. After calling sendto(2) we always get an EINPROGRESS error. We think it is reasonable because connect(2) could also return this error with a non-blocking socket and the connection will be established later. The question is *whether or not the data will be sent* after the connection is established. If I understand correctly, sendto(2) will return the number of bytes of data queued up in the kernel or sent in the SYN packet. Even though the EINPROGRESS is returned. If sendto(2) returns -1, that means that no data is queued up in kernel or sent in the packet. Please correct me if I miss-understand something.
We run the program in our testing environment, and we use tcpdump(1) to capture the packets. From the result we can see there is no any data that is sent. Then we do another testing that after calling sendto(2) the client program will sleep for 5 seconds and then call send(2) to transfer some data.
$ ./client xx.xx.xx.xx ret -1 errno 115The program works well. So that means that after getting a EINPROGRESS error, the program must call send(2) manually. Is it correct? If we want to avoid this problem, we need to set 'net.ipv4.tcp_fastopen' to
0x707?Regards,
- Zheng
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Signature · 3 lines
Regards, Zhi Yong Wu
Quoted 13 lines · 在 2014年3月8日,下午8:56,Zhi Yong Wu <[email protected]> 写道:
Quoted 12 lines · Zheng Liu
Hi all,
Now we are trying to use TCP fast open in our nginx server, and we encounter a problem under non-blocking socket. I appreciate if some one can reply this question. Thanks in advance.
I describe our question here. we have two machines, one is as server and another is as client. 'net.ipv4.tcp_fastopen' on both of them are set to
3. The server program looks like below:
Quoted 6 lines
Quoted 5 lines
...
listenfd =socket(AF_INET, SOCK_STREAM, 0);
bind(listenfd, (struct sockaddr *)&servaddr, sizeof(servaddr)); inttfo_opt= 1;
setsockopt(listenfd, SOL_TCP, TCP_LISTEN_INFO, &tfo_opt, sizeof(tfo_opt));s/TCP_LISTEN_INFO/TCP_FASTOPEN/??
Sigh! Yes, it's a typo. Thanks for pointing it out.
Regards,
- Zheng
Quoted 53 lines
Quoted 46 lines
listen(listenfd, 5);
connfd =accept(listenfd, (struct sockaddr *)NULL, NULL);recv(connfd, &buf, 4096)
...The client program:
...
sockfd =socket(AF_INET, SOCK_STREAM, 0);fcntl(sockfd, F_SETFL, fcntl(sockfd, F_GETFL, 0)|O_NONBLOCK); sendto(sockfd, msg, strlen(msg),MSG_FASTOPEN,(struct sockaddr *)&servaddr, sizeof(servaddr);
recv(sockfd, buf, 4096, 0);
...We use a non-blocking socket to connect the server and send some messages. After calling sendto(2) we always get an EINPROGRESS error. We think it is reasonable because connect(2) could also return this error with a non-blocking socket and the connection will be established later. The question is *whether or not the data will be sent* after the connection is established. If I understand correctly, sendto(2) will return the number of bytes of data queued up in the kernel or sent in the SYN packet. Even though the EINPROGRESS is returned. If sendto(2) returns -1, that means that no data is queued up in kernel or sent in the packet. Please correct me if I miss-understand something.
We run the program in our testing environment, and we use tcpdump(1) to capture the packets. From the result we can see there is no any data that is sent. Then we do another testing that after calling sendto(2) the client program will sleep for 5 seconds and then call send(2) to transfer some data.
$ ./client xx.xx.xx.xx ret -1 errno 115The program works well. So that means that after getting a EINPROGRESS error, the program must call send(2) manually. Is it correct? If we want to avoid this problem, we need to set 'net.ipv4.tcp_fastopen' to
0x707?Regards,
- Zheng
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To unsubscribe from this list: send the line "unsubscribe netdev" in the body of a message to [email protected]
More majordomo info at http://vger.kernel.org/majordomo-info.htmlSignature · 3 lines
Regards, Zhi Yong Wu
Quoted 30 lines · Zheng Liu
Hi all,
Now we are trying to use TCP fast open in our nginx server, and we encounter a problem under non-blocking socket. I appreciate if some one can reply this question. Thanks in advance.
I describe our question here. we have two machines, one is as server and another is as client. 'net.ipv4.tcp_fastopen' on both of them are set to
3. The server program looks like below:... listenfd = socket(AF_INET, SOCK_STREAM, 0); bind(listenfd, (struct sockaddr *)&servaddr, sizeof(servaddr)); int tfo_opt = 1; setsockopt(listenfd, SOL_TCP, TCP_LISTEN_INFO, &tfo_opt, sizeof(tfo_opt)); listen(listenfd, 5); connfd = accept(listenfd, (struct sockaddr *)NULL, NULL); recv(connfd, &buf, 4096) ...The client program:
... sockfd = socket(AF_INET, SOCK_STREAM, 0); fcntl(sockfd, F_SETFL, fcntl(sockfd, F_GETFL, 0)|O_NONBLOCK); sendto(sockfd, msg, strlen(msg), MSG_FASTOPEN, (struct sockaddr *)&servaddr, sizeof(servaddr); recv(sockfd, buf, 4096, 0); ...
Quoted 10 lines
We use a non-blocking socket to connect the server and send some messages. After calling sendto(2) we always get an EINPROGRESS error. We think it is reasonable because connect(2) could also return this error with a non-blocking socket and the connection will be established later. The question is *whether or not the data will be sent* after the connection is established. If I understand correctly, sendto(2) will return the number of bytes of data queued up in the kernel or sent in the SYN packet. Even though the EINPROGRESS is returned. If sendto(2) returns -1, that means that no data is queued up in kernel or sent in the packet. Please correct me if I miss-understand something.
Correct.
http://tools.ietf.org/html/draft-ietf-tcpm-fastopen-07#appendix-A.1
Quoted 4 lines
We run the program in our testing environment, and we use tcpdump(1) to capture the packets. From the result we can see there is no any data that is sent. Then we do another testing that after calling sendto(2)
The first handshake is used to get the Fast Open cookie for future connections. I suspect you didn't enable Fast Open on the server side. What're the output of 'sysctl net.ipv4.tcp_fastopen' on your client and server? pls send the tcpdump traces on both sides as well.
Quoted 13 lines
the client program will sleep for 5 seconds and then call send(2) to transfer some data.
$ ./client xx.xx.xx.xx ret -1 errno 115The program works well. So that means that after getting a EINPROGRESS error, the program must call send(2) manually. Is it correct? If we want to avoid this problem, we need to set 'net.ipv4.tcp_fastopen' to
0x707?Regards,
- Zheng
Hi Yuchung,
Sorry for the late reply because of an urgent issue.
Quoted 45 lines · Yuchung Cheng
Quoted 30 lines · Zheng Liu
Hi all,
Now we are trying to use TCP fast open in our nginx server, and we encounter a problem under non-blocking socket. I appreciate if some one can reply this question. Thanks in advance.
I describe our question here. we have two machines, one is as server and another is as client. 'net.ipv4.tcp_fastopen' on both of them are set to
3. The server program looks like below:... listenfd = socket(AF_INET, SOCK_STREAM, 0); bind(listenfd, (struct sockaddr *)&servaddr, sizeof(servaddr)); int tfo_opt = 1; setsockopt(listenfd, SOL_TCP, TCP_LISTEN_INFO, &tfo_opt, sizeof(tfo_opt)); listen(listenfd, 5); connfd = accept(listenfd, (struct sockaddr *)NULL, NULL); recv(connfd, &buf, 4096) ...The client program:
... sockfd = socket(AF_INET, SOCK_STREAM, 0); fcntl(sockfd, F_SETFL, fcntl(sockfd, F_GETFL, 0)|O_NONBLOCK); sendto(sockfd, msg, strlen(msg), MSG_FASTOPEN, (struct sockaddr *)&servaddr, sizeof(servaddr); recv(sockfd, buf, 4096, 0); ...Quoted 10 lines
We use a non-blocking socket to connect the server and send some messages. After calling sendto(2) we always get an EINPROGRESS error. We think it is reasonable because connect(2) could also return this error with a non-blocking socket and the connection will be established later. The question is *whether or not the data will be sent* after the connection is established. If I understand correctly, sendto(2) will return the number of bytes of data queued up in the kernel or sent in the SYN packet. Even though the EINPROGRESS is returned. If sendto(2) returns -1, that means that no data is queued up in kernel or sent in the packet. Please correct me if I miss-understand something.
Correct.
http://tools.ietf.org/html/draft-ietf-tcpm-fastopen-07#appendix-A.1Quoted 1 line
Quoted 7 lines
Quoted 3 lines
We run the program in our testing environment, and we use tcpdump(1) to capture the packets. From the result we can see there is no any data that is sent. Then we do another testing that after calling sendto(2)
The first handshake is used to get the Fast Open cookie for future connections. I suspect you didn't enable Fast Open on the server side. What're the output of 'sysctl net.ipv4.tcp_fastopen' on your client and server? pls send the tcpdump traces on both sides as well.
Sorry, let me clarify the description please. We can capture the syn packet without data. So that means that client has issued a cookie request. My question is when the data could be sent out.
Here I miss understand the behaviour when the program is the first time to call sendto(2). As RFC draft of TFO described, sendto(2) will return -1 with EINPROGRESS error if the cookie is not available locallly. That means that we need to call write(2) to send the data after the connection is established. Namely, after getting -1 with EINPROGRESS, the caller must call write(2) again later. Now this problem has been solved.
Thanks for your help,
- Zheng