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btrfs: volumes: Remove the meaningless condition of minimal nr_devs when allocating a chunk

PATCH In review Qu Wenruo 4 participants 4 messages Jan 31, 2018 – Mar 14, 2018 Btrfs file system

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Qu Wenruo

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#0 lore raw

PATCH 1/1 btrfs: volumes: Remove the meaningless condition of minimal nr_devs when allocating a chunk

When checking the minimal nr_devs, there is one dead and meaningless condition:

if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This condition is meaningless, @devs_increment has nothing to do with @sub_stripes.

In fact, in btrfs_raid_array[], profile with sub_stripes larger than 1 (RAID10) already has the @devs_increment set to 2.
So no need to multiple it by @sub_stripes.

And above condition is also dead.
For RAID10, @devs_increment * @sub_stripes equals 4, which is also the @devs_min of RAID10.
For other profiles, @sub_stripes is always 1, and since @ndevs is rounded down to @devs_increment, the condition will always be true.

Remove the meaningless condition to make later reader wander less.

---
 fs/btrfs/volumes.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)
fs/btrfs/volumes.c +1 -1
index 215e85e22c8e..cb0a8d27661b 100644
@@ -4729,7 +4729,7 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
 	/* round down to number of usable stripes */
 	ndevs = round_down(ndevs, devs_increment);
 
-	if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
+	if (ndevs < devs_min) {
 		ret = -ENOSPC;
 		goto error;
 	}
Signature · 1 line
2.16.1
Reviewed-by on v1 1/1
#1 lore raw
Quoted 19 lines · Qu Wenruo

When checking the minimal nr_devs, there is one dead and meaningless condition:

if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This condition is meaningless, @devs_increment has nothing to do with @sub_stripes.

In fact, in btrfs_raid_array[], profile with sub_stripes larger than 1 (RAID10) already has the @devs_increment set to 2.
So no need to multiple it by @sub_stripes.

And above condition is also dead.
For RAID10, @devs_increment * @sub_stripes equals 4, which is also the @devs_min of RAID10.
For other profiles, @sub_stripes is always 1, and since @ndevs is rounded down to @devs_increment, the condition will always be true.

Quoted 3 lines

Remove the meaningless condition to make later reader wander less.

Quick question : What exactly is a substripe? Stripe is essentially how many contiguous portions of disk are necessary to satisfy the profile, right? So for raid1 we write 1 copy of the data per device (hence dev_stripes = 1). For DUP we have 2 copies of the data on the same disk hence dev_stripes 2. How does sub_stripes fit in the grand scheme of things?

Quoted 18 lines
---
 fs/btrfs/volumes.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)
fs/btrfs/volumes.c +1 -1
index 215e85e22c8e..cb0a8d27661b 100644
@@ -4729,7 +4729,7 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
 	/* round down to number of usable stripes */
 	ndevs = round_down(ndevs, devs_increment);
 
-	if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
+	if (ndevs < devs_min) {
 		ret = -ENOSPC;
 		goto error;
 	}
#2 lore raw
Quoted 22 lines · Nikolay Borisov
Quoted 19 lines · Qu Wenruo

When checking the minimal nr_devs, there is one dead and meaningless condition:

if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This condition is meaningless, @devs_increment has nothing to do with @sub_stripes.

In fact, in btrfs_raid_array[], profile with sub_stripes larger than 1 (RAID10) already has the @devs_increment set to 2.
So no need to multiple it by @sub_stripes.

And above condition is also dead.
For RAID10, @devs_increment * @sub_stripes equals 4, which is also the @devs_min of RAID10.
For other profiles, @sub_stripes is always 1, and since @ndevs is rounded down to @devs_increment, the condition will always be true.

Quoted 7 lines
Quoted 3 lines

Remove the meaningless condition to make later reader wander less.

Quick question : What exactly is a substripe?

IMHO it is the number of copies inside the RAID0 virtual stripe.

For current RAID10, it's 2 devices as a bundle, using RAID1, then RAID0 these bundles.

Quoted 5 lines

Stripe is essentially how
many contiguous portions of disk are necessary to satisfy the profile, right? So for raid1 we write 1 copy of the data per device (hence dev_stripes = 1). For DUP we have 2 copies of the data on the same disk hence dev_stripes 2. How does sub_stripes fit in the grand scheme of things?

Here we have extra number to describe the behavior. Mostly btrfs_raid_arrary.

For sub_stripes, it should be acts like:

Logical address space:   0                              1G
                         |           RAID10 chunk       |
                         | RAID0 of virtual stripe 1~3  |
                         /               |             \
                        /                |              \
|             Virtual stripe 1|| Virtual stripe 2 || Vritual bundle 3 |
|RAID1 of physical stripe 1~2 |
             /            \
            /              \
|Physical stripe 1| |Physical stripe 2|

And sub_stripes describes how many physical stripes are inside the virtual stripe.

Thanks,
Qu

Quoted 23 lines
Quoted 10 lines
---
 fs/btrfs/volumes.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)
fs/btrfs/volumes.c +0 -0
index 215e85e22c8e..cb0a8d27661b 100644

fs/btrfs/volumes.c static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans, · line 4735

Quoted 8 lines
fs/btrfs/volumes.c +1 -1
@@ -4729,7 +4729,7 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
 	/* round down to number of usable stripes */
 	ndevs = round_down(ndevs, devs_increment);
 
-	if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
+	if (ndevs < devs_min) {
 		ret = -ENOSPC;
 		goto error;
 	}

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Reviewed-by on v1 1/1
#3 lore raw
In reply to Qu Wenruo
Quoted 13 lines · Qu Wenruo

When checking the minimal nr_devs, there is one dead and meaningless condition:

if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This condition is meaningless, @devs_increment has nothing to do with @sub_stripes.

In fact, in btrfs_raid_array[], profile with sub_stripes larger than 1 (RAID10) already has the @devs_increment set to 2.
So no need to multiple it by @sub_stripes.

Quoted 7 lines

And above condition is also dead.
For RAID10, @devs_increment * @sub_stripes equals 4, which is also the @devs_min of RAID10.
For other profiles, @sub_stripes is always 1, and since @ndevs is rounded down to @devs_increment, the condition will always be true.

Remove the meaningless condition to make later reader wander less.

I think the condition is a leftover from times when we did not have the nice raid table and the various values were defined in the function.

Quoted 11 lines
---
 fs/btrfs/volumes.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)
fs/btrfs/volumes.c +0 -0
index 215e85e22c8e..cb0a8d27661b 100644

fs/btrfs/volumes.c static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans, · line 4732

Quoted 5 lines
fs/btrfs/volumes.c +1 -1
@@ -4729,7 +4729,7 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
 	/* round down to number of usable stripes */
 	ndevs = round_down(ndevs, devs_increment);
 
-	if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
+	if (ndevs < devs_min) {

The redundant condtion is duplicated in the error message a few lines below:

4840 if (ndevs < devs_min) {
4841 ret = -ENOSPC;
4842 if (btrfs_test_opt(info, ENOSPC_DEBUG)) {
4843 btrfs_debug(info,
4844 "%s: not enough devices with free space: have=%d minimum required=%d",
4845 __func__, ndevs, min(devs_min,

4846                                     devs_increment * sub_stripes));
                                         ^^^^^^^^^^^^^^^^^^^^^^^^^^^^

so I'll remove it as well.

4847 }
4848 goto error;
4849 }

Quoted 3 lines
fs/btrfs/volumes.c +0 -0
 		ret = -ENOSPC;
 		goto error;
 	}