2.5 fast poll on ppc64
PATCH 1/1 2.5 fast poll on ppc64
Hi,
I was unable to boot 2.5-BK on ppc64 and narrowed it down to the fast poll patch. I found:
offsetof(struct poll_list, entries) == 12 butsizeof(struct poll_list) == 16
This means pp+1 did not match up with pp->entries. Im not sure what the alignment requirements are for a zero length struct (ie is this a compiler bug) but the following patch fixes the problem and also changes ->len to a long to ensure 8 byte alignment of ->entries on 64bit archs.
Anton
===== fs/select.c 1.15 vs edited =====
fs/select.c +2 -2
@@ -362,7 +362,7 @@struct poll_list {struct poll_list *next; -int len; +long len;struct pollfd entries[0 ]; };
@@ -471,7 +471,7 @@ walk->next = pp; walk = pp; -if (copy_from_user (pp+1 , ufds + nfds-i, +if (copy_from_user (pp->entries, ufds + nfds-i,sizeof (struct pollfd )*pp->len)) { err = -EFAULT ; goto out_fds;
Quoted 5 lines · Anton Blanchard
Hi,
I was unable to boot 2.5-BK on ppc64 and narrowed it down to the fast poll patch. I found:
Quoted 9 lines
offsetof(struct poll_list, entries)== 12 butsizeof(struct poll_list)== 16This means pp+1 did not match up with
pp->entries. Im not sure what the alignment requirements are for a zero length struct (ie is this a compiler bug) but the following patch fixes the problem and also changes ->len to a long to ensure 8 byte alignment of ->entries on 64bit archs.
That seems to be the root of the problem: ->entries requires 4 byte alignment, while struct poll_list requires 8 byte alignment. Thus the compiler aligns entries to a 4-byte boundary, and rounds up sizeof(struct poll_list) to 16.
Attached is a small test case that shows the problem on both 64-bit and 32-bit platforms. I'm not sure if this is a gcc bug: the Compaq C compiler on Tru64 and MSVC on Windows generate the same structure layout.
--
Manfred
/*
* Testcase for a possible compiler bug:
* structure with flexible array member.
* offsetof(struct,flexible_member) != sizeof(struct).
*
* That seems to be a violation of 6.7.2.1, constraint 16 of the C99
* standard:
* "First, the size of the structure shall be equal to the offset of the
* last element of an otherwise identical structure that replaces the
* flexible array member with an array of unspecified length. */
#include <stdio.h>
/*
* structure: sizeof() = 4.
* alignment: 2, due to the short.
*/
struct pollfd {
short fd;
char events;
char revents;
};/*
* sizeof: 12
* alignment: 4, due to the int.
*/
struct n2 {
/* offset 0 */
int m;
/* offset 4 */
char n;
/* one byte padding, 'struct pollfd' requires 2 byte alignment */
/* offset 6 */
struct pollfd a[1];
/* offset 10: two bytes padding for 4 byte alignment,
* required for the int in this structure */
};/*
* sizeof: 8.
* XXX
* Is this correct?
* offsetof(struct n1, a) is 6
* --> offsetof(struct n1, a) != sizeof(struct n1)
* XXX
*/
struct n1 {
/* offset 0 */
int m;
/* offset 4 */
char n;
/* one byte padding, 'struct pollfd' required 2 byte alignment */
/* offset 6 */
struct pollfd a[];
};#define offsetof(a,b) \ (int)&((a*)NULL)->b
int main(void)
{
printf("pollfd: sizeof: %d.\n", sizeof(struct pollfd));
printf("fix: sizeof: %d, offsetof: %d.\n", sizeof(struct n2), offsetof(struct n2, a));
printf("var: sizeof: %d, offsetof: %d.\n", sizeof(struct n1), offsetof(struct n1, a));
return 0;
}