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RST business

DISCUSSION Alex Pankratov 4 participants 4 messages Apr 22, 2004

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#0 lore raw

Looking at the hype around 'TCP vulnerability' the following occured to me, and I wonder if it makes any sense -

A host may recieve legitimate RST packet only in response to something that it has previously sent (let's call it a 'trigger').

SEQ/ACK values in RST packet are correlated to SEQ/ACK of the trigger. If the correlation is not there, then RST packet is most certainly spoofed and should be dropped even if its SEQ falls into host's rcpt window.

In other words, it seems to be possible to stregthen ingress RST checking (and thus better protect against blind RST attacks) while maintaining _full RFC compliance_. Here's a how-to sketch.

RFC 793 (page 35) states that for the connection in non-established state -

If the incoming segment has an ACK field, the reset takes its sequence number from the ACK field of the segment, otherwise the reset has sequence number zero and the ACK field is set to the sum of the sequence number and segment length of the incoming segment.

Hence the second RST check (after standard window check) is

	if (! pkt->seq)
		check if we've recently sent a segment without
		an ACK with (pkt->ack - pkt->seq) bytes in it
	else
		check if we've recently sent a segment with ACK
		of (pkt->seq) and with (pkt->ack - pkt->seq)
		bytes in it

If RST passes the check, it's accepted. Otherwise checks continue.

RFC 793 (page 36) states that for the connection in established state -

.. elicit only an empty
acknowledgment segment containing the current send-sequence number and an acknowledgment indicating the next sequence number expected to be received ..

At this point seeing a RST means that
(a) remote host is an ESTABLISHED state
(b) we sent a segment that it considers not to be a part of the current connection

And (b) is something that we can always check since we're now sure about (a).

The above obviously requires keeping some sort of 'outbound history', plus (b) involves some non-trivial logic, which however seems to be doable from the first glance.

Comments ?

Alex

#1 lore raw
Quoted 1 line · Alex Pankratov

Looking at the hype around 'TCP vulnerability'

We're seeing the results of that hype. Lots of peers ringing the NOC to urgently arrange TCP MD5 authentication of their BGP sessions. It looks like lots of managers have read the press and issued directives.

Which is ironic, as we're pretty insistent about configuring MD5 authentication, and so the peer has in the past explicitly requested that we not run BGP authentication. In the past we've assumed that those were Linux peers, but apparently they were just slack.

BGP is particularly vulnerable as they are long-lived (some sessions here are longer than 400 days, so there can be lots of attempts) and the interpretation of RST is dramatic (remove routes learned from that neighbour).

Now if only they would release a Security Advisory about the risks of unauthenticated OSPF and get the same level of response :-)

Quoted 1 line

Comments ?

The essential problem is that RST is the generic way of recovering from a failure condition in the TCP state machine.

So trusting that the values in the remainder of the TCP header are correct is a large leap of faith (perhaps they got trod on by an errant pointer, and perhaps the resulting out-of-range value is why the other end sent us the RST).

If you choose to ignore a RST, and the RST is valid, then you need to ensure that the TCP connection will always time out (thus issuing its own RST).

You can expect, but not be assured of, a RST for each subsequent packet sent on that connection (and maybe that's a cheap way of checking if the original RST is valid, hmmm).

Best wishes,
Glen

#2 lore raw
In reply to Alex Pankratov

If one of the potential causes for RST is that SEQ/ACK synchronization has been lost, then you can't do this.

Quoted 60 lines · Alex Pankratov

Looking at the hype around 'TCP vulnerability' the following occured to me, and I wonder if it makes any sense -

A host may recieve legitimate RST packet only in response to something that it has previously sent (let's call it a 'trigger').

SEQ/ACK values in RST packet are correlated to SEQ/ACK of the trigger. If the correlation is not there, then RST packet is most certainly spoofed and should be dropped even if its SEQ falls into host's rcpt window.

In other words, it seems to be possible to stregthen ingress RST checking (and thus better protect against blind RST attacks) while maintaining _full RFC compliance_. Here's a how-to sketch.

RFC 793 (page 35) states that for the connection in non-established state -

If the incoming segment has an ACK field, the reset takes its sequence number from the ACK field of the segment, otherwise the reset has sequence number zero and the ACK field is set to the sum of the sequence number and segment length of the incoming segment.

Hence the second RST check (after standard window check) is

if (! pkt->seq)
check if we've recently sent a segment without an ACK with (pkt->ack - pkt->seq) bytes in it
else
check if we've recently sent a segment with ACK of (pkt->seq) and with (pkt->ack - pkt->seq) bytes in it

If RST passes the check, it's accepted. Otherwise checks continue.

RFC 793 (page 36) states that for the connection in established state -

.. elicit only an empty
acknowledgment segment containing the current send-sequence number and an acknowledgment indicating the next sequence number expected to be received ..

At this point seeing a RST means that
(a) remote host is an ESTABLISHED state
(b) we sent a segment that it considers not to be a part of the current connection

And (b) is something that we can always check since we're now sure about (a).

The above obviously requires keeping some sort of 'outbound history', plus (b) involves some non-trivial logic, which however seems to be doable from the first glance.

Comments ?

Alex

#3 lore raw

Yeah, sure, I understand that. But how realistis is this synchronization loss ? Ie I cannot immediately think of a sequence of events, which would result in two sides both in Established state with de-synchronized recp/send windows.

Quoted 67 lines · Steve Modica

If one of the potential causes for RST is that SEQ/ACK synchronization has been lost, then you can't do this.

Quoted 60 lines · Alex Pankratov

Looking at the hype around 'TCP vulnerability' the following occured to me, and I wonder if it makes any sense -

A host may recieve legitimate RST packet only in response to something that it has previously sent (let's call it a 'trigger').

SEQ/ACK values in RST packet are correlated to SEQ/ACK of the trigger. If the correlation is not there, then RST packet is most certainly spoofed and should be dropped even if its SEQ falls into host's rcpt window.

In other words, it seems to be possible to stregthen ingress RST checking (and thus better protect against blind RST attacks) while maintaining _full RFC compliance_. Here's a how-to sketch.

RFC 793 (page 35) states that for the connection in non-established state -

If the incoming segment has an ACK field, the reset takes its sequence number from the ACK field of the segment, otherwise the reset has sequence number zero and the ACK field is set to the sum of the sequence number and segment length of the incoming segment.

Hence the second RST check (after standard window check) is

if (! pkt->seq)
check if we've recently sent a segment without an ACK with (pkt->ack - pkt->seq) bytes in it
else
check if we've recently sent a segment with ACK of (pkt->seq) and with (pkt->ack - pkt->seq) bytes in it

If RST passes the check, it's accepted. Otherwise checks continue.

RFC 793 (page 36) states that for the connection in established state -

.. elicit only an empty
acknowledgment segment containing the current send-sequence number and an acknowledgment indicating the next sequence number expected to be received ..

At this point seeing a RST means that
(a) remote host is an ESTABLISHED state
(b) we sent a segment that it considers not to be a part of the current connection

And (b) is something that we can always check since we're now sure about (a).

The above obviously requires keeping some sort of 'outbound history', plus (b) involves some non-trivial logic, which however seems to be doable from the first glance.

Comments ?

Alex