UBI: Fix allocation of volume table
Subsystems (2)
PATCH 1/1 UBI: Fix allocation of volume table
We can't use vmalloc for the buffer used for volume table for some NAND or NOR drivers may pass the buffer to DMA. And the volume table size a.k.a vtbl_size is small so we can use kmalloc or kzalloc for it instead
Signed-off-by JiSheng Zhang <[email protected]>
--- drivers/mtd/ubi/build.c | 6 +++--- drivers/mtd/ubi/vtbl.c | 18 ++++++++---------- 2 files changed, 11 insertions(+), 13 deletions(-)
drivers/mtd/ubi/build.c +3 -3
@@ -605,7 +605,7 @@ out_wl:ubi_wl_close (ubi); out_vtbl:free_internal_volumes (ubi); -vfree (ubi->vtbl); +kfree (ubi->vtbl); out_si:ubi_scan_destroy_si (si);return err;
@@ -1031,7 +1031,7 @@ out_detach:if (do_free)free_user_volumes (ubi);free_internal_volumes (ubi); -vfree (ubi->vtbl); +kfree (ubi->vtbl); out_free:vfree (ubi->peb_buf1);vfree (ubi->peb_buf2);
@@ -1102,7 +1102,7 @@ int ubi_detach_mtd_dev(int ubi_num, int anyway)uif_close (ubi);ubi_wl_close (ubi);free_internal_volumes (ubi); -vfree (ubi->vtbl); +kfree (ubi->vtbl);put_mtd_device (ubi->mtd);vfree (ubi->peb_buf1);vfree (ubi->peb_buf2);
drivers/mtd/ubi/vtbl.c +8 -10
@@ -424,12 +424,11 @@ static struct ubi_vtbl_record *process_lvol(struct ubi_device *ubi,/* Read both LEB 0 and LEB 1 into memory */ ubi_rb_for_each_entry (rb, seb, &sv->root, u.rb) { - leb[seb->lnum] =vmalloc (ubi->vtbl_size); + leb[seb->lnum] =kzalloc (ubi->vtbl_size,GFP_KERNEL );if (!leb[seb->lnum]) { err = -ENOMEM ; goto out_free; } -memset (leb[seb->lnum],0 , ubi->vtbl_size); err =ubi_io_read_data (ubi, leb[seb->lnum], seb->pnum,0 , ubi->vtbl_size);
@@ -470,7 +469,7 @@ static struct ubi_vtbl_record *process_lvol(struct ubi_device *ubi, }/* Both LEB 1 and LEB 2 are OK and consistent */ -vfree (leb[1 ]); +kfree (leb[1 ]);return leb[0 ]; }else {/* LEB 0 is corrupted or does not exist */
@@ -491,13 +490,13 @@ static struct ubi_vtbl_record *process_lvol(struct ubi_device *ubi, goto out_free;ubi_msg ("volume table was restored" ); -vfree (leb[0 ]); +kfree (leb[0 ]);return leb[1 ]; } out_free: -vfree (leb[0 ]); -vfree (leb[1 ]); +kfree (leb[0 ]); +kfree (leb[1 ]);return ERR_PTR (err); }
@@ -515,10 +514,9 @@ static struct ubi_vtbl_record *create_empty_lvol(struct ubi_device *ubi,int i;struct ubi_vtbl_record *vtbl; - vtbl =vmalloc (ubi->vtbl_size); + vtbl =kzalloc (ubi->vtbl_size,GFP_KERNEL );if (!vtbl)return ERR_PTR (-ENOMEM ); -memset (vtbl,0 , ubi->vtbl_size);for (i =0 ; i < ubi->vtbl_slots; i++)memcpy (&vtbl[i], &empty_vtbl_record,UBI_VTBL_RECORD_SIZE );
@@ -528,7 +526,7 @@ static struct ubi_vtbl_record *create_empty_lvol(struct ubi_device *ubi, err =create_vtbl (ubi, si, i, vtbl);if (err) { -vfree (vtbl); +kfree (vtbl);return ERR_PTR (err); } }
@@ -856,7 +854,7 @@ int ubi_read_volume_table(struct ubi_device *ubi, struct ubi_scan_info *si)return 0 ; out_free: -vfree (ubi->vtbl); +kfree (ubi->vtbl);for (i =0 ; i < ubi->vtbl_slots +UBI_INT_VOL_COUNT ; i++) {kfree (ubi->volumes[i]); ubi->volumes[i] =NULL ;
Signature · 1 line
1.6.3.3
Quoted 5 lines · JiSheng Zhang
We can't use vmalloc for the buffer used for volume table for some NAND or NOR drivers may pass the buffer to DMA. And the volume table size a.k.a
vtbl_sizeis small so we can use kmalloc or kzalloc for it insteadSigned-off-by JiSheng Zhang<[email protected]>
I do not have objections if this patch becomes a member of a series of patches which kick vmalloc from whole UBI. Applying just this patch does not make much sense.
You may go through UBI code and try to split large vmalloc-ed buffers on smaller kmalloc-ed ones.
Signature · 2 lines
Best Regards, Artem Bityutskiy (Артём Битюцкий)