Using map_user_kiobuf()
I have been experimenting with a module that returns data to either a user space programme or another module. A memory area is passed in, and the data is written to it. Because the memory may be allocated either by a module or a user programme, a kiobuf seemed a good way of representing it. A layer converts user memory to a kiobuf using map_user_kiobuf().
To test if it would work, I wrote a short test that passed 1,000,000 bytes of memory to a module that wrote a pattern into the memory. The pattern was checked in the user programme to ensure it worked.
The test does work in so much as the pattern checks okay, but kernel memory appears to be corrupted. Trying to run gcc dies with a segmentation violation, and the output of "ps" has the command names replaced with time strings ("00:00:00" or "00:00:05"). X won't shut down properly, and Ctrl-Alt-Del fails to reboot.
The code in the module (without validation and error checking) is:
int test_kiobuf(char* buf)
{
struct kiobuf *iobuf;
int i;
alloc_kiovec(1, &iobuf);
map_user_kiobuf(WRITE, iobuf, buf, TEST_SIZE);
for (i = 0 ; i < iobuf->length; i++)
{
int off = iobuf->offset + i;
int page = off / 4096;
unsigned char* buf = page_address(iobuf->maplist[page]);
buf[off % 4096] = (i & 0xFF);
}
unmap_kiobuf(iobuf);
free_kiovec(1, &iobuf);
return 0;
}The user space programme is:
#include <stdio.h>
#include <fcntl.h>
#include <sys/ioctl.h>
#define TEST_SIZE 1000000
int main(int argc, char *argv[])
{
int fh;
int i;
unsigned char * buf;
buf = (unsigned char *)malloc(TEST_SIZE);
fh = open("/tmp/test", O_CREAT);
if (ioctl(fh, 99, buf) != 0)
perror("ioctl failed");
else
{
for (i = 0; i < TEST_SIZE; i++)
{
if (buf[i] != (i & 0xFF))
printf("%8.8X: %2.2X %2.2X\n", i, i & 0xFF, buf[i]);
}
}
close(fh);
free(buf);
return 0;
}If I change the user programme to initialise the memory to zero everything works okay. It also works if I use copy_to_user() to write a single byte in each page at the beginning of the module code.
This is using kernel 2.4.0-test9.
Does anyone know what I am doing wrong?
John Meikle.
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Hi,
Quoted 5 lines · John Meikle
I have been experimenting with a module that returns data to either a user space programme or another module. A memory area is passed in, and the data is written to it. Because the memory may be allocated either by a module or a user programme, a kiobuf seemed a good way of representing it. A layer converts user memory to a kiobuf using
map_user_kiobuf().
There are a number of fixes pending for 2.4, and released for 2.2, but nothing that would explain the sort of kernel corruption you are reporting --- it sounds as if you are overrunning the end of the kiobuf, but it's hard to know without seeing the real code.
Quoted 9 lines
The code in the module (without validation and error checking) is:
int
test_kiobuf(char* buf){ struct kiobuf *iobuf; int i; alloc_kiovec(1, &iobuf); map_user_kiobuf(WRITE, iobuf, buf, TEST_SIZE);
Careful, you can't touch the buffer for a WRITE map. The READ/WRITE flag is from the point of view of the user, and user write() syscalls don't touch the data in memory! If you want to modify the user buffer, you need to use READ instead.
Cheers,
Stephen
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Steven,
Changing the WRITE to READ does solve the problem, thank you.
I am still confused about why the code failed the way it did. The module managed to write to the full 1,000,000, and the user programme could read it and verify it was correct. Just nothing else worked after that!
Am I the only one who finds the READ/WRITE option back to front?
Regards,
John.
-----Original Message-----
From: [email protected] [mailto:[email protected]]On Behalf Of Stephen C. Tweedie
Sent: 04 December 2000 21:54
To: John Meikle
Cc: [email protected]; Stephen Tweedie
Subject: Re: Using map_user_kiobuf()
Hi,
Quoted 2 lines · John Meikle
I have been experimenting with a module that returns data to either a user space programme or another module. A memory area is passed in, and the
data
Quoted 1 line
is written to it. Because the memory may be allocated either by a module
or
Quoted 2 lines
a user programme, a kiobuf seemed a good way of representing it. A layer converts user memory to a kiobuf using
map_user_kiobuf().
There are a number of fixes pending for 2.4, and released for 2.2, but nothing that would explain the sort of kernel corruption you are reporting --- it sounds as if you are overrunning the end of the kiobuf, but it's hard to know without seeing the real code.
Quoted 9 lines
The code in the module (without validation and error checking) is:
int
test_kiobuf(char* buf){ struct kiobuf *iobuf; int i; alloc_kiovec(1, &iobuf); map_user_kiobuf(WRITE, iobuf, buf, TEST_SIZE);
Careful, you can't touch the buffer for a WRITE map. The READ/WRITE flag is from the point of view of the user, and user write() syscalls don't touch the data in memory! If you want to modify the user buffer, you need to use READ instead.
Cheers,
Stephen
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On Tue, Dec 05, 2000 at 10:15:55AM -0000, John Meikle wrote:
Changing the WRITE to READ does solve the problem, thank you.
I am still confused about why the code failed the way it did. The module managed to write to the full 1,000,000, and the user programme could read it and verify it was correct. Just nothing else worked after that!
Am I the only one who finds the READ/WRITE option back to front?
No, I was just thinking it should be change to USER_READ, USER_WRITE or something a little more obvious.
Stephen?
--cw
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Quoted 4 lines
Am I the only one who finds the READ/WRITE option back to front?
No, I was just thinking it should be change to
USER_READ,USER_WRITEor something a little more obvious.
Eh, read data from userspace and write data to userspace? Oops.
FROM_USERTO_USER
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Yes, this is better
--cw
Quoted 4 lines · Albert D. Cahalan
Am I the only one who finds the READ/WRITE option back to front?
No, I was just thinking it should be change to
USER_READ,USER_WRITEor something a little more obvious.
Eh, read data from userspace and write data to userspace? Oops.
FROM_USER
TO_USER
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