New: Unexpected failure when write to a file with two file descriptor
https://bugzilla.kernel.org/show_bug.cgi?id=218850
Bug ID: 218850
Summary: Unexpected failure when write to a file with two file
descriptor
Product: File System
Version: 2.5
Hardware: All
OS: Linux
Status: NEW
Severity: normal
Priority: P3
Component: ext4
Assignee: [email protected]
Reporter: [email protected]
Regression: No
Created attachment 306300
--> https://bugzilla.kernel.org/attachment.cgi?id=306300&action=editreproduce.c
Hi,
I mounted an ext4 image, created a file, and created a link to it, then I wrote to these two files, and I failed with a specific read and write order. I can reproduce this with the latest linux kernel
https://git.kernel.org/torvalds/t/linux-6.9-rc7.tar.gz
The following is the triggering script:
``` dd if=/dev/zero of=ext4-0.img bs=1M count=120 mkfs.ext4 ext4-0.img g++ -static reproduce.c losetup /dev/loop0 ext4-0.img mkdir /root/mnt ./a.out ```
After run the script, you will see the error message:
``` write failure ```
The contents of reproduce.c :
```
#include <assert.h>
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
#include <stdarg.h>
#include <stddef.h>
#include <unistd.h>
#include <pthread.h>
#include <errno.h>
#include <dirent.h>
#include <string>
#include <sys/mount.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <sys/ioctl.h>
#include <sys/wait.h>
#include <sys/xattr.h>
#include <sys/mount.h>
#include <sys/statfs.h>
#include <fcntl.h>
#define ALIGN 4096
void* align_alloc(size_t size) {
void *ptr = NULL;
int ret = posix_memalign(&ptr, ALIGN, size);
if (ret) {
printf("align error\n");
exit(1);
}
return ptr;
}
int main()
{
char *buf_15 = (char*)align_alloc(4096*20);
memset(buf_15, 'a', 4096*20);
char *buf_4 = (char*)align_alloc(4096*20);
memset(buf_4, 'a', 4096*20);
mount("/dev/loop0", "/root/mnt", "f2fs", 0, "");
creat("/root/mnt/a", S_IRWXG);
link("/root/mnt/a", "/root/mnt/b");
int fd_a = open("/root/mnt/a", O_RDWR);
int fd_b = open("/root/mnt/b", O_RDWR | O_DIRECT);
lseek(fd_a, 100, SEEK_SET);
write(fd_a, buf_15, 9900);
read(fd_b, buf_4, 73728);
int state = write(fd_b, buf_15, 65536);
if (state == -1) {
printf("write failure\n");
}
return 0;
}
```If I move the statement read(fd_b, buf_4, 73728); before the first write operation, or modify the size 73728 to a smaller one, such as 63728, then this script will not fail.
Did I do anything wrong?
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[Bug 218850] Unexpected failure when write to a file with two file descriptor
https://bugzilla.kernel.org/show_bug.cgi?id=218850
--- Comment #1 from Chi ([email protected]) ---
So sorry, The mount function call should be mount("/dev/loop0", "/root/mnt", "ext4", 0, "");
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[Bug 218850] Unexpected failure when write to a file with two file descriptor
In reply to [email protected]https://bugzilla.kernel.org/show_bug.cgi?id=218850
--- Comment #2 from Chi ([email protected]) ---
Could you please help me review this report? I am still able to reproduce the issue with the following test case:
```
#include <assert.h>
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
#include <stdarg.h>
#include <stddef.h>
#include <unistd.h>
#include <pthread.h>
#include <errno.h>
#include <dirent.h>
#include <string>
#include <sys/mount.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <sys/ioctl.h>
#include <sys/wait.h>
#include <sys/xattr.h>
#include <sys/mount.h>
#include <sys/statfs.h>
#include <fcntl.h>
#define ALIGN 4096
void* align_alloc(size_t size) {
void *ptr = NULL;
int ret = posix_memalign(&ptr, ALIGN, size);
if (ret) {
printf("align error\n");
exit(1);
}
return ptr;
}
int main()
{
char *buf_15 = (char*)align_alloc(4096*20);
memset(buf_15, 'a', 4096*20);
char *buf_4 = (char*)align_alloc(4096*20);
memset(buf_4, 'a', 4096*20);
mount("/dev/loop0", "/root/mnt", "ext4", 0, "");
creat("/root/mnt/a", S_IRWXG);
link("/root/mnt/a", "/root/mnt/b");
int fd_a = open("/root/mnt/a", O_RDWR);
int fd_b = open("/root/mnt/b", O_RDWR | O_DIRECT);
lseek(fd_a, 100, SEEK_SET);
write(fd_a, buf_15, 9900);
read(fd_b, buf_4, 73728);
int state = write(fd_b, buf_15, 65536);
if (state == -1) {
printf("write failure\n");
}
return 0;
}
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[Bug 218850] Unexpected failure when write to a file with two file descriptor
In reply to [email protected]https://bugzilla.kernel.org/show_bug.cgi?id=218850
Theodore Tso ([email protected]) changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|NEW |RESOLVED
CC| |[email protected]
Resolution|--- |INVALID--- Comment #3 from Theodore Tso ([email protected]) ---
Hint: check the return value of all system calls. In particular, check to
see what the read(fd_b, buf_4, 73728) returns. Check to see what the size of
the file is after write(fd_a, buf_15, 9900), and then reflect on what happens if the read ends up hitting the end of file marker, and what the offset of fd_b is after the short read when hitting EOF.
Finally, read the documentation for the O_DIRECT flag in the NOTES section of the open man page[1], and understand what the requirements are for O_DIRECT writes, in particular about the alignment requirements are of the starting
offset when performing an O_DIRECT write (or O_DIRECT) read. Then also check
on the errno return (for example replace the printf("write failure\n") with perror("write").
[1] https://man7.org/linux/man-pages/man2/open.2.html
In any case, this is not a bug, and this is not a good place for you to be asking for instruction in basic Unix system call programming.
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