Skip to contentSkip to conversation

: Make `before' relation unambiguous

PATCH New Gerrit Renker 1 participant 1 message Mar 20, 2007

Subsystems (2)
lore
Share & tools
lore
#0 lore raw

PATCH 12/31 : Make `before' relation unambiguous

Problem:
--------
before48(a, b) returns the same as before48(b, a) for all a, b which are 2^47 apart (modulo-2^48). The reason is that the difference a-b is used and `true' is returned whenever 2^47 <= a-b <= 2^48-1. This has the disadvantage that a positive difference a-b = 2^47 can not be distinguished from a negative difference b-a = 2^47. As a result, an ambiguity arises in 2^47 cases.

Fix:
----
The fix is the same as the one suggested for TCP: define a `before' b whenever 1 <= b-a <= 2^47-1 (positive signed 48-bit numbers). As a result, the ambiguity disappears. (Note: we could have used dccp_delta_seqno, but Arnaldo's concept of using shift and subtraction requires fewer operations).

The patch further defines after48 as a macro, since it is in actual fact just before48 with the parameters swapped (this mirrors the TCP solution).

---
 net/dccp/dccp.h |    7 ++-----
 1 files changed, 2 insertions(+), 5 deletions(-)
net/dccp/dccp.h +2 -5
index e6c95e9..287a040 100644
@@ -124,14 +124,11 @@ static inline s64 dccp_delta_seqno(const u64 seqno1, const u64 seqno2)
 /* is seq1 < seq2 ? */
 static inline int before48(const u64 seq1, const u64 seq2)
 {
-	return (s64)((seq1 << 16) - (seq2 << 16)) < 0;
+	return (s64)((seq2 << 16) - (seq1 << 16)) > 0;
 }
 
 /* is seq1 > seq2 ? */
-static inline int after48(const u64 seq1, const u64 seq2)
-{
-	return (s64)((seq2 << 16) - (seq1 << 16)) < 0;
-}
+#define after48(seq1, seq2)	before48(seq2, seq1)
 
 /* is seq2 <= seq1 <= seq3 ? */
 static inline int between48(const u64 seq1, const u64 seq2, const u64 seq3)
Signature · 1 line
1.5.0.3