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genirq/matrix: Choose CPU for assigning interrupts based on allocated IRQs

PATCH In review Long Li 3 participants 3 messages Nov 1, 2018 IRQ

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Long Li

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#0 lore raw

PATCH v2 1/1 genirq/matrix: Choose CPU for assigning interrupts based on allocated IRQs

From: Long Li <[email protected]>

On a large system with multiple devices of the same class (e.g. NVMe disks, using managed IRQs), the kernel tends to concentrate their IRQs on several CPUs.

The issue is that when NVMe calls irq_matrix_alloc_managed(), the assigned CPU tends to be the first several CPUs in the cpumask, because they check for cpumap->available that will not change after managed IRQs are reserved.

In irq_matrix->cpumap, "available" is set when IRQs are allocated earlier in the IRQ allocation process. This value is caculated based on
1. how many unmanaged IRQs are allocated on this CPU
2. how many managed IRQs are reserved on this CPU

But "available" is not accurate in accouting the real IRQs load on a given CPU.

For a managed IRQ, it tends to reserve more than one CPU, based on cpumask in irq_matrix_reserve_managed. But later when actually allocating CPU for this IRQ, only one CPU is allocated. Because "available" is calculated at the time managed IRQ is reserved, it tends to indicate a CPU has more IRQs than it's actually assigned.

When a managed IRQ is assigned to a CPU in irq_matrix_alloc_managed(), it decreases "allocated" based on the actually assignment of this IRQ to this CPU. Unmanaged IRQ also decreases "allocated" after allocating an IRQ on this CPU. For this reason, checking "allocated" is more accurate than checking "available" for a given CPU, and result in a more evenly distributed IRQ across all CPUs.

---
 kernel/irq/matrix.c | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)
kernel/irq/matrix.c +3 -3
index 6e6d467f3dec..a51689e3e7c0 100644
@@ -128,7 +128,7 @@ static unsigned int matrix_alloc_area(struct irq_matrix *m, struct cpumap *cm,
 static unsigned int matrix_find_best_cpu(struct irq_matrix *m,
 					const struct cpumask *msk)
 {
-	unsigned int cpu, best_cpu, maxavl = 0;
+	unsigned int cpu, best_cpu, min_allocated = UINT_MAX;
 	struct cpumap *cm;
 
 	best_cpu = UINT_MAX;
@@ -136,11 +136,11 @@ static unsigned int matrix_find_best_cpu(struct irq_matrix *m,
 	for_each_cpu(cpu, msk) {
 		cm = per_cpu_ptr(m->maps, cpu);
 
-		if (!cm->online || cm->available <= maxavl)
+		if (!cm->online || cm->allocated > min_allocated)
 			continue;
 
 		best_cpu = cpu;
-		maxavl = cm->available;
+		min_allocated = cm->allocated;
 	}
 	return best_cpu;
 }
Signature · 1 line
2.14.1
#1 lore raw

Long,

Quoted 10 lines · Long Li

On a large system with multiple devices of the same class (e.g. NVMe disks, using managed IRQs), the kernel tends to concentrate their IRQs on several CPUs.

The issue is that when NVMe calls irq_matrix_alloc_managed(), the assigned CPU tends to be the first several CPUs in the cpumask, because they check for cpumap->available that will not change after managed IRQs are reserved.

In irq_matrix->cpumap, "available" is set when IRQs are allocated earlier in the IRQ allocation process. This value is caculated based on

calculated

Quoted 5 lines

1. how many unmanaged IRQs are allocated on this CPU
2. how many managed IRQs are reserved on this CPU

But "available" is not accurate in accouting the real IRQs load on a given CPU.

Quoted 8 lines

For a managed IRQ, it tends to reserve more than one CPU, based on cpumask in irq_matrix_reserve_managed. But later when actually allocating CPU for this IRQ, only one CPU is allocated. Because "available" is calculated at the time managed IRQ is reserved, it tends to indicate a CPU has more IRQs than it's actually assigned.

When a managed IRQ is assigned to a CPU in irq_matrix_alloc_managed(), it decreases "allocated" based on the actually assignment of this IRQ to this CPU.

decreases?

Quoted 1 line

Unmanaged IRQ also decreases "allocated" after allocating an IRQ on this CPU.

ditto

Quoted 3 lines

For this reason, checking "allocated" is more accurate than checking "available" for a given CPU, and result in a more evenly distributed IRQ across all CPUs.

Again, this approach is only correct for managed interrupts. Why?

Assume that total vector space size = 10

CPU 0:
allocated = 8
available = 1

i.e. there are 2 managed reserved, but not assigned interrupts

CPU 1:
allocated = 7
available = 0

i.e. there are 3 managed reserved, but not assigned interrupts

Now allocate a non managed interrupt:

irq_matrix_alloc()

	cpu = find_best_cpu() <-- returns CPU1

	---> FAIL

The allocation fails because it cannot allocate from the managed reserved space. The managed reserved space is guaranteed even if the vectors are not assigned. This is required to make hotplug work and to allow late activation without breaking the guarantees.

Non managed has no guarantees, it's a best effort approach, so it can fail. But the fail above is just wrong.

You really need to treat managed and unmanaged CPU selection differently.

Thanks,

tglx

#2 lore raw
Quoted 76 lines

Subject: Re: [Patch v2] genirq/matrix: Choose CPU for assigning interrupts based on allocated IRQs

Long,

Quoted 4 lines · Long Li

On a large system with multiple devices of the same class (e.g. NVMe disks, using managed IRQs), the kernel tends to concentrate their IRQs on several CPUs.

Quoted 8 lines

The issue is that when NVMe calls irq_matrix_alloc_managed(), the assigned CPU tends to be the first several CPUs in the cpumask, because they check for
cpumap->available that will not change after managed IRQs are reserved.

In irq_matrix->cpumap, "available" is set when IRQs are allocated earlier in the IRQ allocation process. This value is caculated based on

calculated

Quoted 5 lines

1. how many unmanaged IRQs are allocated on this CPU 2. how many managed IRQs are reserved on this CPU

But "available" is not accurate in accouting the real IRQs load on a given CPU.

Quoted 8 lines

For a managed IRQ, it tends to reserve more than one CPU, based on cpumask in irq_matrix_reserve_managed. But later when actually allocating CPU for this IRQ, only one CPU is allocated. Because "available" is calculated at the time managed IRQ is reserved, it tends to indicate a CPU has more IRQs than it's actually assigned.

When a managed IRQ is assigned to a CPU in irq_matrix_alloc_managed(), it decreases "allocated" based on the actually assignment of this IRQ to this

CPU.

decreases?

Quoted 1 line

Unmanaged IRQ also decreases "allocated" after allocating an IRQ on this

CPU.

ditto

Quoted 3 lines

For this reason, checking "allocated" is more accurate than checking "available" for a given CPU, and result in a more evenly distributed IRQ across all CPUs.

Again, this approach is only correct for managed interrupts. Why?

Assume that total vector space size = 10

CPU 0:
allocated = 8
available = 1

i.e. there are 2 managed reserved, but not assigned interrupts

CPU 1:
allocated = 7
available = 0

i.e. there are 3 managed reserved, but not assigned interrupts

Now allocate a non managed interrupt:

irq_matrix_alloc()

	cpu = find_best_cpu() <-- returns CPU1

	---> FAIL

The allocation fails because it cannot allocate from the managed reserved space. The managed reserved space is guaranteed even if the vectors are not assigned. This is required to make hotplug work and to allow late activation without breaking the guarantees.

Quoted 4 lines

Non managed has no guarantees, it's a best effort approach, so it can fail. But the fail above is just wrong.

You really need to treat managed and unmanaged CPU selection differently.

Thank you for the explanation. I will send another patch to do it properly.

Long

Quoted 4 lines

Thanks,

tglx