mm: no need to check return value of debugfs_create functions

mm/memblock.c +0 -0

index 022d4cbb3618..18ee657fb918 100644

On Tue 22-01-19 16:21:13, Greg KH wrote:
[...]

Quoted 5 lines

mm/memblock.c +0 -0

index 022d4cbb3618..18ee657fb918 100644

mm/memblock.c DEFINE_SHOW_ATTRIBUTE(memblock_debug); · line 2004

Quoted 9 lines

mm/memblock.c +1 -2

@@ -1998,8 +1998,7 @@ DEFINE_SHOW_ATTRIBUTE(memblock_debug);
 static int __init memblock_init_debugfs(void)
 {
 	struct dentry *root = debugfs_create_dir("memblock", NULL);
-	if (!root)
-		return -ENXIO;
+
 	debugfs_create_file("memory", 0444, root,
 			    &memblock.memory, &memblock_debug_fops);
 	debugfs_create_file("reserved", 0444, root,

I haven't really read the whole patch but this has just hit my eyes. Is this a correct behavior?

Documentations says:
* @parent: a pointer to the parent dentry for this file. This should be a
* directory dentry if set. If this parameter is NULL, then the
* file will be created in the root of the debugfs filesystem.

so in case of failure we would get those debugfs files outside of their intended scope. I believe it is much more correct to simply not create anything, no?

Quoted 20 lines · Michal Hocko

On Tue 22-01-19 16:21:13, Greg KH wrote:
[...]

Quoted 5 lines

mm/memblock.c +0 -0

index 022d4cbb3618..18ee657fb918 100644

mm/memblock.c DEFINE_SHOW_ATTRIBUTE(memblock_debug); · line 2004

Quoted 9 lines

mm/memblock.c +1 -2

@@ -1998,8 +1998,7 @@ DEFINE_SHOW_ATTRIBUTE(memblock_debug);
 static int __init memblock_init_debugfs(void)
 {
 	struct dentry *root = debugfs_create_dir("memblock", NULL);
-	if (!root)
-		return -ENXIO;
+
 	debugfs_create_file("memory", 0444, root,
 			    &memblock.memory, &memblock_debug_fops);
 	debugfs_create_file("reserved", 0444, root,

I haven't really read the whole patch but this has just hit my eyes. Is this a correct behavior?

Quoted 8 lines

Documentations says:
* @parent: a pointer to the parent dentry for this file. This should be a
* directory dentry if set. If this parameter is NULL, then the
* file will be created in the root of the debugfs filesystem.

so in case of failure we would get those debugfs files outside of their intended scope. I believe it is much more correct to simply not create anything, no?

If debugfs_create_dir() returns NULL, then something is really wrong (you passed it an invalid pointer as the parent dentry, or free memory is gone), so there's nothing you can do except keep moving forward and take that result and pass it as any parent pointer you want to. Your code logic should never care if a debugfs file is created or not, it is "fire and forget".

And any result of a debugfs call, like this one, that is to be passed into another debugfs call, will work just fine if the first one failed (the second one usually will also fail, which is fine.)

Also, and this is the biggest problem, everyone gets the return value check wrong thinking NULL will be an error, it is one type of error, but other ones are also returned and no one checks them properly. So just don't check at all, that is the design goal here.

Quoted 30 lines · Greg KH

Quoted 20 lines · Michal Hocko

On Tue 22-01-19 16:21:13, Greg KH wrote:
[...]

Quoted 5 lines

mm/memblock.c +0 -0

index 022d4cbb3618..18ee657fb918 100644

mm/memblock.c DEFINE_SHOW_ATTRIBUTE(memblock_debug); · line 2004

Quoted 9 lines

mm/memblock.c +1 -2

@@ -1998,8 +1998,7 @@ DEFINE_SHOW_ATTRIBUTE(memblock_debug);
 static int __init memblock_init_debugfs(void)
 {
 	struct dentry *root = debugfs_create_dir("memblock", NULL);
-	if (!root)
-		return -ENXIO;
+
 	debugfs_create_file("memory", 0444, root,
 			    &memblock.memory, &memblock_debug_fops);
 	debugfs_create_file("reserved", 0444, root,

I haven't really read the whole patch but this has just hit my eyes. Is this a correct behavior?

Quoted 8 lines

Documentations says:
* @parent: a pointer to the parent dentry for this file. This should be a
* directory dentry if set. If this parameter is NULL, then the
* file will be created in the root of the debugfs filesystem.

so in case of failure we would get those debugfs files outside of their intended scope. I believe it is much more correct to simply not create anything, no?

Quoted 6 lines

If debugfs_create_dir() returns NULL, then something is really wrong (you passed it an invalid pointer as the parent dentry, or free memory is gone), so there's nothing you can do except keep moving forward and take that result and pass it as any parent pointer you want to. Your code logic should never care if a debugfs file is created or not, it is "fire and forget".

OK, but does it make any sense to continue creating files when you know that the parent directory has failed to create? What kind of advantage does this have?

Quoted 8 lines

And any result of a debugfs call, like this one, that is to be passed into another debugfs call, will work just fine if the first one failed (the second one usually will also fail, which is fine.)

Also, and this is the biggest problem, everyone gets the return value check wrong thinking NULL will be an error, it is one type of error, but other ones are also returned and no one checks them properly. So just don't check at all, that is the design goal here.

sounds like a poor design goal to me but not mine code to maintain so...

On Tue, Jan 22, 2019 at 05:07:01PM +0100, Michal Hocko wrote:

Quoted 1 line

sounds like a poor design goal to me but not mine code to maintain so...

The design goal was to make it as simple as possible to use, and that includes "you do not care about the return value". Now we do have to return a value because some people need that for when they want to make a subdirectory, or remove the file later on, otherwise I would have just had everything be a void return function :)