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how compiler decide the range of real numbers in C...

DISCUSSION RAM_LOCK 2 participants 2 messages Jul 30, 2009

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#0 lore raw

Say 16 bit compiler (for ex Turbo C) uses 2's compliment to find the range of signed integer.
Say for 16 bit n=16. Now applying 2's compliment equation : -2^(n-1) to 2^(n-1) -1
so for n=16 : The range is -32768 to 32767

This is ok. The question arises when it tell about real constant's range. For 16 bit compiler the range of real constant is : -3.4e38 to 3.4e38

How they arrived to this real constant range?

Can any one share the mathematical calculation behind it?

thnx,
RAM_LOCK

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#1 lore raw
Quoted 6 lines · RAM_LOCK

Say 16 bit compiler (for ex Turbo C) uses 2's compliment to find the range of signed integer.
Say for 16 bit n=16. Now applying 2's compliment equation : -2^(n-1) to 2^(n-1) -1
so for n=16 : The range is -32768 to 32767

Quoted 6 lines

This is ok. The question arises when it tell about real constant's range. For 16 bit compiler the range of real constant is : -3.4e38 to 3.4e38

How they arrived to this real constant range?

Can any one share the mathematical calculation behind it?

	http://en.wikipedia.org/wiki/IEEE_754-1985
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Glynn Clements <[email protected]>