misunderstanding of the virtual memory
Hi,
I'm Benjamin and I'm studying the kernel. I write you this email because I've a trouble with the mmu and the virtual memory. I try to understand how a program (user land) can write something into the stack (push ebp, for example), indeed, the program works with virtual address (between 0x00000 and 0x8... if my memory is good) but at the hardware side the address is not the same (that's why mmu was created, if I'm right).
My problem is the following : how the data is wrote on the physical memory. When I try a strace (kernel 2.6.32 on a simple program) I have no hint on the transfer of data. Moreover, according to the wikipedia web page on syscall (
https://en.wikipedia.org/wiki/System_call#The_library_as_an_intermediary
), a call is not managed by the kernel. So, how the transfer between virtual memory and physical memory is possible ?
I hope my email is understandable, I tried to put words on my troubles.
Thanks a lot for your help and have a nice day.
Benjamin.
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Quoted 9 lines · Ben Teissier
Hi,
I'm Benjamin and I'm studying the kernel. I write you this email because I've a trouble with the mmu and the virtual memory. I try to understand how a program (user land) can write something into the stack (push ebp, for example), indeed, the program works with virtual address (between
0x00000and0x8... if my memory is good) but at the hardware side the address is not the same (that's why mmu was created, if I'm right).
Yes, this is the purpose of pages tables; to map virtual addresses to real memory addresses (more precisely virtual memory _pages_ to real memory pages).
Quoted 8 lines
My problem is the following : how the data is wrote on the physical memory. When I try a strace (kernel 2.6.32 on a simple program) I have no hint on the transfer of data. Moreover, according to the wikipedia web page on syscall (
https://en.wikipedia.org/wiki/System_call#The_library_as_an_intermediary
), a call is not managed by the kernel. So, how the transfer between virtual memory and physical memory is possible ?
That is because writing to a memory location in userspace isn't an operation that requires a syscall or any kind of kernel intervention at all. It is an assembly store instruction executed directly on the CPU by the program. The only time the kernel is involved in a store operation is if the virtual address translation doesn't exist in the TLB (or is write-protected, etc..), in which case the hardware generates a fault so the kernel take the required action to populate the TLB with the translation.
Hope this answers your question.
Seth
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2013/5/9, Seth Jennings <[email protected]>:
Quoted 39 lines · Ben Teissier
Quoted 10 lines
Hi,
I'm Benjamin and I'm studying the kernel. I write you this email because I've a trouble with the mmu and the virtual memory. I try to understand how a program (user land) can write something into the stack (push ebp, for example), indeed, the program works with virtual address (between
0x00000and0x8... if my memory is good) but at the hardware side the address is not the same (that's why mmu was created, if I'm right).Yes, this is the purpose of pages tables; to map virtual addresses to real memory addresses (more precisely virtual memory _pages_ to real memory pages).
Quoted 8 lines
My problem is the following : how the data is wrote on the physical memory. When I try a strace (kernel 2.6.32 on a simple program) I have no hint on the transfer of data. Moreover, according to the wikipedia web page on syscall (
https://en.wikipedia.org/wiki/System_call#The_library_as_an_intermediary
), a call is not managed by the kernel. So, how the transfer between virtual memory and physical memory is possible ?That is because writing to a memory location in userspace isn't an operation
that requires a syscall or any kind of kernel intervention at all. It is an
assembly store instruction executed directly on the CPU by the program. The
only time the kernel is involved in a store operation is if the virtual address
translation doesn't exist in the TLB (or is write-protected, etc..), in which
case the hardware generates a fault so the kernel take the required action to
populate the TLB with the translation.
Quoted 5 lines
Hope this answers your question.
Seth
Hi,
Your answer is perfect, thanks a lot for your help !
Benjamin.
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