removing a snapshot that is outside the subvolume directory fails, sorta
Well, it fails the way that I'm trying to do it.
kernel: 2.6.31.9-174.fc12.x86_64 btrfs-progs: btrfs-progs-0.19-9.fc12.x86_64
On a new filesystem:
$ cd /mnt/btrfs1 $ btrfsctl -S subvol1 . operation complete Btrfs Btrfs v0.19 $ btrfsctl -s snapofsubvol1 subvol1 operation complete Btrfs Btrfs v0.19 $ btrfsctl -D snapofsubvol1 subvol1 ioctl:: No such file or directory
$ btrfsctl -S subvol2 . operation complete Btrfs Btrfs v0.19 --------> # cd subvol2 <------------ $ btrfsctl -s snapofsubvol2 subvol2 operation complete Btrfs Btrfs v0.19 $ btrfsctl -D snapofsubvol2 subvol2 operation complete Btrfs Btrfs v0.19
AHA, I figured it out!
$ btrfsctl -D snapofsubvol1 subvol1/..
I don't know if that's the intended syntax or if it's accidental, but I'll go ahead and send this as an FYI if anyone has the same issue. Maybe it's obvious to some, but it wasn't to me.
Quoted 6 lines · Brian Neu
Well, it fails the way that I'm trying to do it.
kernel: 2.6.31.9-174.fc12.x86_64 btrfs-progs: btrfs-progs-0.19-9.fc12.x86_64On a new filesystem:
Quoted 10 lines
$ cd /mnt/btrfs1 $ btrfsctl -S subvol1 . operation complete Btrfs Btrfs v0.19 $ btrfsctl -s snapofsubvol1 subvol1 operation complete Btrfs Btrfs v0.19 $ btrfsctl -D snapofsubvol1 subvol1 ioctl:: No such file or directory
Correct; the syntax should be:
$ btrfsctl -D snapofsubvol1 .
the last parameters is directory where the snapshot is.
Quoted 8 lines
$ btrfsctl -S subvol2 . operation complete Btrfs Btrfs v0.19 --------> # cd subvol2 <------------ $ btrfsctl -s snapofsubvol2 subvol2 operation complete Btrfs Btrfs v0.19
To me this last step doesn't work. It works only if the "cd subvol2" command is not executed.
Quoted 10 lines
$ btrfsctl -D snapofsubvol2 subvol2 operation complete Btrfs Btrfs v0.19AHA, I figured it out!
$ btrfsctl -D snapofsubvol1 subvol1/..I don't know if that's the intended syntax or if it's accidental, but I'll
go ahead and send this as an FYI if anyone has the same issue. Maybe it's obvious to some, but it wasn't to me.
Yes it is obvious :-) Because "subvol1/.." is like "." .
BR
G.Baroncelli
Signature · 2 lines
gpg key@ keyserver.linux.it: Goffredo Baroncelli (ghigo) <kreijackATinwind.it> Key fingerprint = 4769 7E51 5293 D36C 814E C054 BF04 F161 3DC5 0512