apparent sleep
Hi.
Following LDD3, I am dealing with wait queues, on a 2.6.10.
My loop is like:
while(enough()){
prepare_to_wait(&queue_head, &queue_entry, TASK_INTERRUPTIBLE);
atomic_set(&flag, 0);
if (!atomic_read(&flag, 0))
schedule();
finish_wait(&queue_head, &queue_entry);
}
My intention is to wake up the process at each loop by issuing CTRL^D.
Here is what happens:
the first time the process yields the processor, it actually sleeps and I have to give it a CTRL^D in order to put it again in running state; unfortunately, in the following loops, although it calls the schedule() function, it magically regains the processor putting hisself in a running state (since it runs, I guess the state is a running one).
In a few words, the while loop has thousands of iterations, but CTRL^D is needed only during the first one.
Thank you all
Quoted 3 lines · Milton Krutt
Hi.
Following LDD3, I am dealing with wait queues, on a 2.6.10.
Please use a modern kernel, 2.6.10 is _very_ old and no one can do anything about it, and those that could, have long forgotten what was in it.
good luck,
greg k-h