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apparent sleep

DISCUSSION Milton Krutt 2 participants 2 messages Mar 23, 2015

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#0 lore raw

Hi.

Following LDD3, I am dealing with wait queues, on a 2.6.10.

My loop is like:

while(enough()){

prepare_to_wait(&queue_head, &queue_entry, TASK_INTERRUPTIBLE);

atomic_set(&flag, 0);

if (!atomic_read(&flag, 0))

	schedule();

finish_wait(&queue_head, &queue_entry);

		}

My intention is to wake up the process at each loop by issuing CTRL^D.

Here is what happens:

the first time the process yields the processor, it actually sleeps and I have to give it a CTRL^D in order to put it again in running state; unfortunately, in the following loops, although it calls the schedule() function, it magically regains the processor putting hisself in a running state (since it runs, I guess the state is a running one).

In a few words, the while loop has thousands of iterations, but CTRL^D is needed only during the first one.

Thank you all

#1 lore raw
Quoted 3 lines · Milton Krutt

Hi.

Following LDD3, I am dealing with wait queues, on a 2.6.10.

Please use a modern kernel, 2.6.10 is _very_ old and no one can do anything about it, and those that could, have long forgotten what was in it.

good luck,

greg k-h